The Total solution for NCERT class 6-12
Find the approximate value of┬аf┬а(5.001),where┬аf┬а(x) =┬аx3┬атИТ7x2┬а+ 15.
Let┬аx┬а= 5 and ╬Фx┬а=0.001. Then, we have:
Hence, the approximate value of┬аf┬а(5.001)is тИТ34.995.