Question -
Answer -
The equation of the given curve is x2 + y2 −2x − 3 = 0.
On differentiating with respect to x,we have:
Now, the tangents are parallel to the x-axisif the slope of the tangent is 0.
But, x2 + y2 −2x − 3 = 0 for x = 1.
y2 =4⇒
Hence, the points at which the tangents areparallel to the x-axis are (1, 2) and (1, −2).