Question -
Answer -
The equation of the given curve is y = x3 −11x + 5.
The equation of the tangent to the givencurve is given as y = x − 11 (which is of theform y = mx + c).
∴Slope of the tangent = 1
Now, the slope of the tangent to the given curve atthe point (x, y) is given by, 
Then, we have:
When x = 2, y =(2)3 − 11 (2) + 5 = 8 − 22 + 5 = −9.
When x = −2, y =(−2)3 − 11 (−2) + 5 = −8 + 22 + 5 = 19.
Hence, the required points are (2, −9) and (−2, 19). But,both these points should satisfy the equation of the tangent as there would bepoint of contact between tangent and the curve. ∴ (2, −9) is the required point as (−2, 19) is notsatisfying the given equation of tangent.