Question -
Answer -
The equation of the given parabola is┬аy2┬а=4ax.
On differentiating┬аy2┬а=4ax┬аwith respect to┬аx, we have:
тИ┤The slope of the tangent at
is┬а
Then, the equation of thetangent atis given by,
y┬атИТ 2at┬а=
Now, the slope of thenormal atis given by,
Thus, the equation of the normal at (at2, 2at)is given as:
