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Question -

A ladder 5 m long is leaning against a wall. The bottom ofthe ladder is pulled along the ground, away from the wall, at the rate of 2cm/s. How fast is its height on the wall decreasing when the foot of the ladderis 4 m away from the wall?



Answer -

Let y m be the height of thewall at which the ladder touches. Also, let the foot of the ladder be mawayfrom the wall.

Then, byPythagoras theorem, we have:

x2 + y2 = 25 [Length of the ladder = 5 m]

Then, the rate of change of height (y) withrespect to time (t) isgiven by,

It is given that

Now, when x = 4 m, we have:

Hence, the height of theladder on the wall is decreasing at the rate of

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