The Total solution for NCERT class 6-12
x3┬атАУ 8y3┬а+ 27z3┬а+18xyz= (x)3┬а+ (-2y)3┬а+ (3z)3┬атАУ 3 x xx (-2y) (3 z)= (x тАУ y + 3z) (x2┬а+ 4y2┬а+ 9z2┬а+2xy + 6yz тАУ 3zx)