The Total solution for NCERT class 6-12
(i) (x2 + y2 + z2 –xy + yz + zx) by (x + y – z)= x3 +y3 – z3 + 3xyz(ii) (x2 + 4y2 + z2 + 2xy + xz– 2yz) by (x – 2y – z)= (x -2y-z) [x2 + (-2y)2 + (-z)2 -xx (- 2y) – (-2y) (z) – (-z) (x)]= x3 + (-2y)3 + (-z)3 –3x (-2y) (-z)= x3 – 8y3 – z3 – 6xyz(iii) x2 + 4y2 + 2xy – 3x + 6y + 9 by x – 2y +3= (x – 2y + 3) (x2 + 4y2 + 9 + 2xy + 6y – 3x)= (x)3 + (-2y)3 + (3)3 – 3 x xx (-2y) x 3 = x3 – 8y3 + 27 + 18xy(iv) 9x2 + 25y3 + 15xy + 12x – 20y + 16 by 3x –5y + 4= (3x -5y + 4) [(3x)2 + (-5y)2 + (4)2 –3x x (-5y) (-5y x 4) – (4 x 3x)]= (3x)3 + (-5y)3 + (4)3 – 3 x3x (-5y) x 4= 27x3 – 12573 + 64 + 180xy