The Total solution for NCERT class 6-12
We know thata3┬а+ b3┬а+ c3┬атАУ 3abc = (a + b +c) (a2┬а+ b2┬а+ c2┬атАУ ab тАУ bc тАУ ca)a3┬а+ 8b3┬а+ 64c3┬атАУ 24abc= (a)3┬а+ (2b)3┬а+ (4c)3┬атАУ 3 x ax 2b x 4c= (a + 2b + 4c) [(a)2┬а+ (2b)2┬а+ (4c)2┬а-ax 2b тАУ 2b x 4c тАУ 4c x a]= (a + 2b + 4c) (a2┬а+ 4b2┬а+ 16c2┬атАУ2ab тАУ 8bc тАУ 4ca)