The Total solution for NCERT class 6-12
(2x – 3y)3 + (4z – 2x)3 + (3y –4z)3∵ 2x – 3y + 4z – 2x + 3y – 4z = 0∴ (2x –3y)3 + (4z – 2x)3 + (3y – 4z)3= (2x – 3y) (4z – 2x) (3y – 4z) {∵ x3 +y3 + z3 = 3xyz if x + y + z = 0}