The Total solution for NCERT class 6-12
x3 – 12x(x – 4) – 64= x3 – 12x2 + 48x – 64= (x)3 – 3 x x2 x 4 + 3 x x x (4)2– (4)3= (x – 4)3= (x – 4) (x – 4) (x – 4)