The Total solution for NCERT class 6-12
Answer - 11 : -
a3x3 – 3a2bx2 +3ab2x – b3= (ax)3 – 3 x (ax)2 x b + 3 x ax x(b)2– (b)3= (ax – b)3= (ax – b) (ax – b) (ax – b)