The Total solution for NCERT class 6-12
64a3 + 125b3 + 240a2b+ 300ab2= (4a)3 + (5b)3 + 3 x (4a)2 x5b + 3(4a) + (5b)2= (4a + 5b)3= (4a + 5b) (4a + 5b) (4a + 5b)