The Total solution for NCERT class 6-12
x(x3 – y3) + 3xy(x – y)= x(x – y) (x2 + xy + y2) + 3xy(x – y)= x(x – y) (x2 + xy + y2 + 3y)= x(x – y) (x2 + xy + y2 + 3y)