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Question -

Factorize

x3 + x тАУ 3x2 тАУ 3



Answer -

x3┬а+ x тАУ 3x2┬атАУ 3
x3┬атАУ 3a2┬а+ x тАУ 3
тЗТ┬аx2(x тАУ 3) + 1(x тАУ 3)
= (x тАУ 3) (x2┬а+ 1)

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