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Question -

(a тАУ b + c)2 + (b тАУ c + a)2 + 2(a тАУ b + c) (b тАУ c + a)



Answer -

(aтАУ┬аb┬а+c)2┬а+┬а( b- c+a)2┬а+2(a┬атАУ b +c) (b тАУ c┬а+a)┬а ┬а ┬а┬а{тИ╡┬аa2┬а+b2┬а+2ab┬а=(a + b)2}
=[a тАУ b + c + b- c + a]2
= (2a)2┬а=4a2

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