MENU
Question -

X3 тАУ 2x2y + 3xy2 тАУ 6y3



Answer -

x3┬атАУ2x2y + 3xy2┬атАУ┬а6y3
=x2(x тАУ 2y)┬а+┬а3y2(xтАУ 2y)
=(x тАУ 2y) (x2┬а+ 3y2)

Comment(S)

Show all Coment

Leave a Comment

Free - Previous Years Question Papers
Any questions? Ask us!
×