Question -
Answer -
Given quadratic equation,
x2 + x + 1/√2 = 0
It can be rewritten as,
√2x2 +√2x +1 = 0
On comparing it with ax2 + bx + c =0, we have
a =√2, b =√2, and c =1
So, the discriminant of the given equation is
D = b2 –4ac =(√2)2 – 4 × √2 × 1 = 2 – 4√2 =2(1 – 2√2)
Hence, the required solutions are:
