Question -
Answer -
Given : In the figure AB тКе BC, DC тКе BC and DE тКе AC
To prove : тИЖCED ~ тИЖABC.
Proof: AB тКе BC
тИаB = 90┬░
and тИаA + тИаACB = 90┬░ тАж.(i)
DC тКе BC
тИаDCB = 90┬░
=> тИаACB + тИаDCA = 90┬░ тАж.(ii)
From (i) and (ii)
тИаA = тИаDCA
Now in тИЖCED and тИЖABC,
тИаE = тИаB (each 90┬░)
тИаDEA or тИаDCE = тИаA (proved)
тИЖCED ~ тИЖABC (AA axiom)
Hence proved.