Question -
Answer -
Let the sides of the two squares be x m and y m.
Therefore, their perimeter will be 4x and 4y respectively
And area of the squares will be x2 and y2 respectively.
Given,
4x тАУ 4y = 24
x тАУ y = 6
x = y + 6
Also,┬аx2┬а+┬аy2┬а=468
тЗТ (6┬а+┬аy2)┬а+┬аy2┬а=468
тЗТ 36┬а+┬аy2┬а+ 12y┬а+┬аy2┬а=468
тЗТ 2y2┬а+ 12y┬а+ 432 = 0
тЗТ┬аy2┬а+ 6y тАУ 216 = 0
тЗТ┬аy2┬а+ 18y┬атАУ 12y┬атАУ216 = 0
тЗТ┬аy(y┬а+18) -12(y┬а+ 18) = 0
тЗТ (y┬а+ 18)(y┬атАУ 12) = 0
тЗТ┬аy┬а= -18, 12
As we know, the side of a square cannot benegative.
Hence, the sides of the squares are 12 m and(12 + 6) m = 18 m.