Question -
Answer -
Total distance covered = x km
Fare for 1st kilometre = Rs 8
Fare for the rest of the distance = Rs (x − 1) 5
Total fare = Rs [8 + (x − 1) 5]
y = 8 + 5x −5
y = 5x + 3
5x − y + 3 = 0
It can be observed that point (0, 3) and 
satisfies the above equation. Therefore, these are the solutions ofthis equation.
| x | 0 | 
|
| y | 3 | 0 |
The graph of this equation is constructed as follows.
Here,it can be seen that variable x and y arerepresenting the distance covered and the fare paid for that distancerespectively and these quantities may not be negative. Hence, only those valuesof x and y which are lying in the 1st quadrantwill be considered.