Question -
Answer -
Given cot (cos-1 3/5+ sin-1 x) = 0
On rearranging we get,
(cos-1 3/5+ sin-1 x) = cot-1 (0)
(Cos-1 3/5+ sin-1 x) = π/2
We know that cos-1 x+ sin-1 x = π/2
Then sin-1 x= π/2 – cos-1 x
Substituting the abovein (cos-1 3/5 + sin-1 x) = π/2 we get,
(Cos-1 3/5+ π/2 – cos-1 x) = π/2
Now on rearranging weget,
(Cos-1 3/5– cos-1 x) = π/2 – π/2
(Cos-1 3/5– cos-1 x) = 0
Therefore Cos-1 3/5= cos-1 x
On comparing the aboveequation we get,
x = 3/5