Question -
Answer -
The given determinant is
We have:
M13 = 
M23 = 
M33 = 
∴A13 = cofactor of a13 =(−1)1+3 M13 = (z − y)
A23 = cofactor of a23 =(−1)2+3 M23 = − (z − x) = (x − z)
A33 = cofactor of a33 =(−1)3+3 M33 = (y − x)
We know that Δ is equal tothe sum of the product of the elements of the second row with theircorresponding cofactors.
Hence, 