The Total solution for NCERT class 6-12
x = 4, y – 3, z = 2⇒ 4x2 + y2 +25z2 + 4xy – 10yz – 20zx= (2x)2 + (y)2 + (5z)2 + 2 x2 xx y-2 x y x 5z – 2 x 5z x 2x= (2x + y- 5z)2= (2 x 4 + 3- 5 x 2)2= (8 + 3- 10)2= (11 – 10)2= (1)2 = 1