The Total solution for NCERT class 6-12
2x + 3y = 8 and xy = 2Now, (2x + 3y)2 = (2x)2 + (3y)2 +2 x 2x x 3y⇒ (8)2 = 4x2 +9y2 + 12xy⇒ 64 = 4X2 + 9y2 +12 x 2⇒ 64 = 4x2 + 9y2 +24⇒ 4x2 + 9y2 =64 – 24 = 40∴ 4x2 + 9y2 =40