The Total solution for NCERT class 6-12
2x + 3y = 8 and xy = 2Now, (2x + 3y)2┬а= (2x)2┬а+ (3y)2┬а+2 x 2x x 3yтЗТ┬а(8)2┬а= 4x2┬а+9y2┬а+ 12xyтЗТ 64 = 4X2┬а+ 9y2┬а+12 x 2тЗТ 64 = 4x2┬а+ 9y2┬а+24тЗТ 4x2┬а+ 9y2┬а=64 тАУ 24 = 40тИ┤ 4x2┬а+ 9y2┬а=40