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Question -

What is the probability that an ordinary year has 53 Sundays?



Answer -

Given: A year which includes 52 weeks and one day.
By using the formula,
P (E) = favourable outcomes / total possible outcomes
So, we now have to determine the probability of that one day being Sunday
Total number of possible outcomes is 7
n(S) = 7
E = {M, T, W, T, F, S, SU}
n (E) = 1
P (E) = n (E) / n (S)
= 1 / 7

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