Question -
Answer -
Given: Two unbiaseddice are thrown.
By using the formula,
P (E) = favourableoutcomes / total possible outcomes
So, we now have todetermine the probability of getting the sum of digits on dice greater than 10
Total number ofpossible outcomes is 62=36
n (S) = 36
Let E be the event ofgetting same number on all the three dice
E = {(5,6) (6,5)(6,6)}
n (E) = 3
P (E) = n (E) / n (S)
= 3 / 36
= 1/12