Question -
Answer -
Given: Numberedtickets from 1 to 20.
By using the formula,
P (E) = favourableoutcomes / total possible outcomes
To find theprobability of the ticket drawn having a number which is a multiple of 3 or 7.
We know that, oneticket is drawn from a lot of mixed number.
Total possibleoutcomes are
n (S) = 20C1 =20
Let E be the event ofgetting ticket which has number that is multiple of 3 or 7
E ={3,6,9,12,15,18,7,14}
n (E) = 8
P (E) = n (E) / n (S)
= 8 / 20
= 2/5