Question -
Answer -
Given: Five cards aredrawn from a pack of 52 cards.
By using the formula,
P (E) = favourableoutcomes / total possible outcomes
Five cards are drawnat random,
Total possibleoutcomes are 52C5
n (S) = 2598960
(i) Let E be theevent that exactly only one ace is present
n (E) = 4C148C4 =778320
P (E) = n (E) / n (S)
= 778320 / 2598960
= 3243/10829
(ii) Let E be theevent that at least one ace is present
E = {1 or 2 or 3 or 4ace(s)}
n (E) = 4C148C4+4C248C3+4C348C2+4C448C1 =886656
P (E) = n (E) / n (S)
= 886656 / 2598960
= 18472/54145