Question -
Answer -
Given: A die is thrown.
The total number of outcomes is six, n (S) = 6
By using the formula,
P (E) = favourable outcomes / total possible outcomes
(i) Let E be the event of getting a prime number
E = {2, 3, 5}
n (E) = 3
P (E) = n (E) / n (S)
= 3 / 6
= ┬╜
(ii) Let E be the event of getting 2 or 4
E = {2, 4}
n (E) = 2
P (E) = n (E) / n (S)
= 2 / 6
= 1/3
(iii) Let E be the event of getting a multiple of 2 or 3
E = {2, 3, 4, 6}
n (E) = 4
P (E) = n (E) / n (S)
= 4 / 6
= 2/3