Question -
| Class | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
| Frequency | 5 | 10 | 20 | 5 | 10 |
Answer -
To find the mean deviation from the median, firstly let uscalculate the median.
Median is the middle term of the Xi,
Here, the middle term is 25
So, Median = 25
| Class Interval | xi | fi | Cumulative Frequency | |di| = |xi – M| | fi |di| |
| 0-10 | 5 | 5 | 5 | 20 | 100 |
| 10-20 | 15 | 10 | 15 | 10 | 100 |
| 20-30 | 25 | 20 | 35 | 0 | 0 |
| 30-40 | 35 | 5 | 91 | 10 | 50 |
| 40-50 | 45 | 10 | 101 | 20 | 200 |
| | Total = 50 | | | Total = 450 |
MD=
= 1/50 × 450
= 9
∴ Themean deviation is 9