Question -
| Number of calls | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| Frequency | 14 | 21 | 25 | 43 | 51 | 40 | 39 | 12 |
Compute the meandeviation about the median.
Answer -
To find the mean deviation from the median, firstly let uscalculate the median.
We know, Median is the even term, (3+5)/2 = 4
So, Median = 8
Let xi┬а=Number of calls
And, fi┬а= Frequency
| xi | fi | Cumulative Frequency | |di| = |xi┬атАУ M| = |xi┬атАУ 61| | fi┬а|di| |
| 0 | 14 | 14 | 4 | 56 |
| 1 | 21 | 35 | 3 | 63 |
| 2 | 25 | 60 | 2 | 50 |
| 3 | 43 | 103 | 1 | 43 |
| 4 | 51 | 154 | 0 | 0 |
| 5 | 40 | 194 | 1 | 40 |
| 6 | 39 | 233 | 2 | 78 |
| 7 | 12 | 245 | 3 | 36 |
| | | | Total = 366 |
| Total = 245 | | | |
N = 245
MD=
= 1/245 ├Ч 336
= 1.49
тИ┤ Themean deviation is 1.49.