Question -
| I Income in тВ╣ | II Income in тВ╣ |
| 4000 | 3800 |
| 4200 | 4000 |
| 4400 | 4200 |
| 4600 | 4400 |
| 4800 | 4600 |
| 4800 |
| 5800 |
Answer -
Let us calculate the mean deviation for the first data set.
Since the data is arranged in ascending order,
4000, 4200, 4400, 4600, 4800
Median = 4400
Total observations = 5
We know that,
MD=
Where, |di| = |xi┬атАУ M|
| xi | |di| = |xi┬атАУ 4400| |
| 4000 | 400 |
| 4200 | 200 |
| 4400 | 0 |
| 4600 | 200 |
| 4800 | 400 |
| Total | 1200 |
MD=
= 1/5 ├Ч 1200
= 240
Let us calculate the mean deviation for the second data set.
Since the data is arranged in ascending order,
3800, 4000, 4200, 4400, 4600, 4800, 5800
Median = 4400
Total observations = 7
We know that,
MD=
Where, |di| = |xi┬атАУ M|
| xi | |di| = |xi┬атАУ 4400| |
| 3800 | 600 |
| 4000 | 400 |
| 4200 | 200 |
| 4400 | 0 |
| 4600 | 200 |
| 4800 | 400 |
| 5800 | 1400 |
| Total | 3200 |
MD=
= 1/7 ├Ч 3200
= 457.14
тИ┤ TheMean Deviation of set 1 is 240 and set 2 is 457.14