The Total solution for NCERT class 6-12
ex log a┬а+ ealog x┬а+ ea log a
Given:
f (x) = ex log a┬а+ea log x┬а+ ea log a
We know that,
elog f(x)┬а=┬аf(x)
So,
f(x) = ax┬а+ xa┬а+ aa
Differentiate on both the sides with respect to x, we get