The Total solution for NCERT class 6-12
By furthersimplification
= 2 sin 4x┬аcos (тАУ2x) + 2 sin 4x
It can be written as
= 2 sin 4x┬аcos2x┬а+ 2 sin 4x
Taking common terms
= 2 sin 4x┬а(cos2x┬а+ 1)
Using the formula
= 2 sin 4x┬а(2 cos2┬аx┬атАУ1 + 1)
We get
= 2 sin 4x┬а(2 cos2┬аx)
= 4cos2┬аx┬аsin4x
= R.H.S.