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Question -

Prove that:┬аcos2┬а2x┬атАУ cos2┬а6x┬а=sin 4x┬аsin 8x



Answer -


We get
= [2 cos 4x cos (-2x)] [-2 sin 4x sin (-2x)]
It can be written as
= [2 cos 4x cos 2x] [тАУ2 sin 4x (тАУsin 2x)]
So we get
= (2 sin 4x cos 4x) (2 sin 2x cos 2x)
= sin 8x sin 4x
= RHS

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