The Total solution for NCERT class 6-12
It is given that
tan x = – 5/12
We can write it as
We know that
1 + tan2 x= sec2 x
1 + (-5/12)2 =sec2 x
Substituting thevalues
1 + 25/144 = sec2 x
sec2 x= 169/144
sec x = ± 13/12
Here x lies in thesecond quadrant so the value of sec x will be negative
sec x = – 13/12