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Question -

The sum of the numerator and denominator of a fraction is 3 less than twice the denominator. If the numerator and denominator are decreased by 1, the numerator becomes half the denominator. Determine the fraction. (C.B.S.E. 2001C)



Answer -

Let the numerator of a fraction = x
and denominator = y
Then fraction = x/y
According to the conditions given,
x + y = 2y – 3
=> x + y – 2y = -3

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