Question -
Answer -
Let first person has amount of money = Rs. x
and second person has = Rs. y
Now according to the conditions given,
x + 100 = 2(y – 100)
=> x + 100 = 2y – 200
=> x – 2y = – 200 – 100
=> x – 2y = -300 ………(i)
and 6(x – 10) = (y + 10)
=> 6x – 60 = y + 10
=> 6x – y = 10 + 60
=> 6x – y = 70 ……….(ii)
From (i), x = 2y – 300
Substituting the value of x in (ii)
6(2y – 300) – y = 70
=> 12y – 1800 – y = 70
=> 11y = 70 + 1800 = 1870
y = 170
x = 2y – 300 = 2 x 170 -300 = 340 – 300 = 40
First person has money = ₹ 40
and second person has = ₹ 170