Question -
Answer -
Solution:
Given equations are 2x+ y = 6 and 2x – y + 2 = 0
Table for equation 2x+ y – 6 = 0, for x = 0, y = 6, for y = 0, x = 3.
Table for equation 2x– y + 2 = 0, for x = 0, y = 2, for y = 0,x = – 1
Let A1 andA2 represent the areas of triangles ACE and BDE respectively.
Let, Area of triangleformed with x -axis = T1
T1 =Area of △ACE = ½ × AC × PE
T1 = ½× 4 × 4 = 8
And Area of triangleformed with y – axis = T2
T1 =Area of △BDE = ½ × BD × QE
T1 = ½× 4 × 1 = 2
T1:T2 =8:2 = 4:1
Hence, the pair ofequations intersect graphically at point E(1,4)
i.e., x = 1 and y = 4.