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Question -

Form the pair of linear equations in the following problems, and find their solutions graphically.



Answer -

(i) 10 students of Class X took part in a Mathematics quiz. If the number of girls is 4 more than the number of boys, find the number of boys and girls who took part in the quiz.
(ii) 5 pencils and 7 pens together cost 50, whereas 7 pencils and 5 pens together cost 46. Find the cost of one pencil and that of one pen.

Answer
(i)Let there are x number of girls and y number of boys. As per the given question, the algebraic expression can be represented as follows.
x +y = 10
x– y = 4
Now, for x+y = 10 or x = 10−y, the solutions are;

x

5

4

6

y

5

6

4

For x – y = 4 or x = 4 + y, the solutions are;

x

4

5

3

y

0

1

-1

The graphical representation is as follows;
From the graph, it can be seen that the given lines cross each other at point (7, 3). Therefore, there are 7 girls and 3 boys in the class.

(ii) Let 1 pencil costs Rs.x and 1 pen costs Rs.y.
According to the question, the algebraic expression cab be represented as;
5x + 7y = 50
7x + 5y = 46
For, 5x + 7y = 50 or  x = (50-7y)/5, the solutions are;

x

3

10

-4

y

5

0

10

For 7x + 5y = 46 or x = (46-5y)/7, the solutions are;

x

8

3

-2

y

-2

5

12

Hence, the graphical representation is as follows;
From the graph, it is can be seen that the given lines cross each other at point (3, 5).
So, the cost of a pencil is 3/- and cost of a pen is 5/-.

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