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Question -

Is * defined on the set {1, 2, 3, 4, 5} by a * b =LCM of a and b a binary operation? Justify your answer.



Answer -

LCM

1

2

3

4

5

1

1

2

3

4

5

2

2

2

6

4

10

3

3

5

3

12

15

4

4

4

12

4

20

5

5

10

15

20

5

In the givencomposition table, all the elements are not in the set {1, 2, 3, 4, 5}.

If weconsider a = 2 and b = 3, a * b = LCMof a and b = 6  {1, 2, 3, 4, 5}.

Thus, * is not abinary operation on {1, 2, 3, 4, 5}.

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