Question -
Answer -
Given:
The points(2, -1, 3) and (-1, 2, 1)
By using the section formula,
Let C(x, y, z) be any point on the given plane and C divides AB in ratio k: 1
Then, m = k and n = 1
A(2, -1, 3) and B(-1, 2, 1)
Coordinates of C are:
On comparing we get,
[-k + 2] / [k + 1] = x
[2k – 1] / [k + 1] = y
[-k + 3] / [k + 1] = z
We know that x + y + z = 5
5(k + 1) = 4
5k + 5 = 4
5k = 4 – 5
5k = – 1
k = -1/5
∴We can saythat, the plane divides AB externally in the ratio 1:5