Question -
Answer -
Given:
The points A (2, -3, 4) and B (8, 0, 10)
By using the section formula,
Let Point C(x, y, 8), and C divides AB in ratio k: 1
So, m = k and n = 1
A(2, -3, 4) and B(8, 0, 10)
Coordinates of C are:
On comparing we get,
[10k + 4] / [k + 1] = 8
10k + 4 = 8(k + 1)
10k + 4 = 8k + 8
10k – 8k = 8 – 4
2k = 4
k = 4/2
= 2
Here C divides AB in ratio 2:1
x = [8k + 2] / [k + 1]
= [8(2) + 2] / [2 + 1]
= [16 + 2] / [3]
= 18/3
= 6
y = -3 / [k + 1]
= -3 / [2 + 1]
= -3 / 3
= -1
∴ The Coordinates of C are (6, -1, 8).