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Question -

Find the point on y-axis which is equidistant from the points (3, 1, 2) and (5, 5, 2).



Answer -

Given:
The points (3, 1, 2) and (5, 5, 2)
We know x = 0 and z = 0 on y-axis
Let R(0, y, 0) any point on the y-axis
According to the question:
RA = RB
RA2 = RB2
By using the formula,
The distance between any two points (a, b, c) and (m, n, o) is given by,

So,

We know, RA2 = RB2

13+ (y – 1)2 = (y – 5)2 + 29

y2+ 1 – 2y + 13 = y2+ 25 – 10y + 29

10y – 2y = 54 – 14

8y = 40

y = 40/8

= 5

Thepoint R (0, 5, 0) on y-axis is equidistant from (3, 1, 2) and (5, 5, 2).

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