Question -
Answer -
Solution:
(i) (5,2, 3)
In this case, since x, y and z all three are positive thenoctant will be XOYZ
(ii) (-5,4, 3)
In this case, since x is negative and y and z are positive thenthe octant will be X′OYZ
(iii) (4,-3, 5)
In this case, since y is negative and x and z are positive thenthe octant will be XOY′Z
(iv) (7,4, -3)
In this case, since z is negative and x and y are positive thenthe octant will be XOYZ′
(v) (-5,-4, 7)
In this case, since x and y are negative and z is positive thenthe octant will be X′OY′Z
(vi) (-5,-3, -2)
In this case, since x, y and z all three are negative thenoctant will be X′OY′Z′
(vii) (2,-5, -7)
In this case, since z and y are negative and x is positive thenthe octant will be XOY′Z′
(viii) (-7,2, -5)
In this case, since x and z are negative and x is positive thenthe octant will be X′OYZ′