Question -
| Number of girls in a family | 0 | 1 | 2 |
| Number of families | 211 | 814 | 475 |
If a family is chosen at random, compute the probability that it has:
(i) No girl
(ii) 1 girl
(iii) 2 girls
(iv) at most one girl
(v) more girls than boys
Answer -
The total number of trials is 1500.
Remember the empirical or experimental or observed frequency approach to probability.
If n be the total number of trials of an experiment and A is an event associated to it such that A happens in m-trials. Then the empirical probability of happening of event A is denoted by 
and is given by (i) Let A be the event of having no girl.
The number of times A happens is 211.
Therefore, we have
(ii) Let B be the event of having one girl.
The number of times B happens is 814.
Therefore, we have
(iii) Let C be the event of having two girls.
The number of times C happens is 475.
Therefore, we have
(iv) Let D be the event of having at most one girl.
The number of times D happens is 
. Therefore, we have
(v) Let E be the event of having more girls than boys.
The number of times E happens is 475.
Therefore, we have