Question -
Answer -
Given:
x2 + y2 +6x – 14y – 1 = 0…. (1)
So the centre =[(-6/2), -(-14/2)]
= [-3, 7]
x2 + y2 –4x + 10y – 2 = 0… (2)
So the centre =[-(-4/2), (-10/2)]
= [2, -5]
We know that theequation of the circle is given by,
(x – x1) (x– x2) + (y – y1) (y – y2) = 0
(x + 3) (x – 2) + (y –7) (y + 5) = 0
Upon simplification weget
x2 +3x – 2x – 6 + y2 – 7y + 5y – 35 = 0
x2 + y2 +x – 2y – 41 = 0
∴The equation of thecircle is x2 + y2 + x – 2y – 41 = 0