Question -
Answer -
Given:
p = 4, α = 15°
The equation of theline in normal form is given by
We know that, cos15° = cos (45° – 30°) = cos45°cos30° + sin45°sin30°
Cos (A – B) = cos Acos B + sin A sin B
So,
And sin 15 = sin(45° – 30°) = sin 45° cos 30° – cos 45° sin 30°
Sin (A – B) = sin Acos B – cos A sin B
So,
Now, by using theformula,
x cos α + y sin α= p
Now, substitute thevalues, we get
(√3+1)x +(√3-1) y =8√2
∴ The equation of linein normal form is (√3+1)x +(√3-1) y = 8√2.