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Question -

Find the equation to the straight line which passes through the point (5,6) and has intercepts on the axes
(i) Equal in magnitude and both positive

(ii) Equal in magnitude but opposite in sign



Answer -

(i) Equal in magnitude andboth positive

Given:

a = b

Let us find theequation of line cutoff intercepts from the axes.

By using the formula,

The equation of theline is x/a + y/b = 1

x/a + y/a = 1

x + y = a

The line passesthrough the point (5, 6)

Hence, the equationsatisfies the points.

5 + 6 = a

a = 11

The equation of theline is x + y = 11

(ii) Equal in magnitude butopposite in sign

Given:

b = -a

Let us find theequation of line cutoff intercepts from the axes.

By using the formula,

The equation of theline is x/a + y/b = 1

x/a + y/-a = 1

x – y = a

The line passesthrough the point (5, 6)

Hence, the equationsatisfies the points.

5 – 6 = a

a = -1

The equation of theline is x – y = -1

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